Tuesday, 26 November 2019

real analysis - Showing convergence of the sequence of functions defined by fn=frac1nx+1





Let fn:(0,1)R:x1nx+1



Does (fn)n0 converge pointwise? Uniformly?




My attempt:



Let x(0,1). Then limnfn=0. Hence, x(0,1):fn(x)0 and we deduce that (fn) converges pointswise to 0:(0,1)R:x0




Now, since supx(0,1)|1nx+10|=110



it follows that (fn) does not converge uniformly.




Questions:



(1) Is this correct?




(2) Are there alternatives to show that it is not uniform convergent?



Answer



Yes, it is correct. I think that that way of proving that the convergence is not uniform is the simplest one. However, I would have added an explanation for the equalitysupx(0,1)|1nx+1|=1.


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