∫√cosx+1cscxdx
Sorry for the bad formatting, I still need to learn math jax. I am trying to integrate this by u-sub but am stuck. Looking at the equation I can see somewhere I will probably have to use the fact the cscx=1/sinx. My hunch is I choose u to be something in the numerator, but is there an identity i'm not seeing?
Answer
Guide:
∫(cosx+1)12cscxdx=∫sinx(cosx+1)12dx
Try substitution u=cosx+1.
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