Friday, 19 December 2014

A question about a detail in Bell's "Primer of Infinitesimal Analysis"



On p.35,36 of J.L. Bell's A Primer of Infinitesimal Analysis (2nd ed.), Bell uses the book's basic methods to derive the formula for the area of a circle based on the circumference. Where s(x) is a function for the length of a certain portion of the circumference of a circle, and C(x) is a formula for a portion of the area of a circle, and ε is a nilpotent infinitesimal quantity, he derives the formula C(x)=12rs(x) and goes on to say, "Since C(0)=s(0)=0, the Constancy Principle now yields C(x)=\frac{1}{2}rs(x)."



The "Constancy Principle" in question is that if f is a real valued function with f'(x) constantly 0, then f is constant; alternatively, f is constant if f(x+\varepsilon)=f(x) for all x and infinitesimal \varepsilon.



My question is, how does C(0)=s(0)=0 allow use of the constancy principle, and why does this follow from it? The steps before and after this make total sense to me, but I don't see what's going on here, nor in similar steps in later proofs.


Answer



Let f(x)=C(x)-\frac{1}{2}rs(x). Then f'(x)=C'(x)-\frac{1}{2}rs'(x)=0 for all x. By the Constancy Principle, f is constant, so f(x)=f(0)=C(0)-\frac{1}{2}rs(0)=0 for all x. That is, C(x)=\frac{1}{2}rs(x) for all x.



No comments:

Post a Comment

real analysis - How to find lim_{hrightarrow 0}frac{sin(ha)}{h}

How to find \lim_{h\rightarrow 0}\frac{\sin(ha)}{h} without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...