$$\sum_{n=1}^{\infty }\frac{1}{n^{n}}$$
I have no idea how to even start computing this series. I do know, however, that this series definitely converges. Solving it numerically results in a solution close to 1.29.
But, how would one compute this series analytically?
Answer
This sum has no known closed form, but the following relation is true:
$$\sum_{k=1}^{\infty}k^{-k} = \int_0^1x^{-x}dx.$$
See here.
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