Tuesday, 23 December 2014

Show that the sequence is bounded?

Show that the sequence 3n+sin2n6nnN is bounded.



I know that 0sin2n1, so 3n6n=123n+sin2n6n3n+16n



So it is easy to see that it is bounded below by 12, but I can't figure out how to show it is bounded above.

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