limx→∞(logk+1(x)x)=limx→∞((k+1)logk(x)x1)=limx→∞((k+1)(k)logk−1(x)x)=limx→∞((k+1)!x)⇒0
I used L'Hospital to get to limx→∞((k+1)(k)logk−1(x)x)
But from there I don't understand how to get limx→∞((k+1)!x)
Any help would be appreciated, thanks in advance.
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