Saturday, 13 December 2014

limit of log(x)(k+1)/x

limx(logk+1(x)x)=limx((k+1)logk(x)x1)=limx((k+1)(k)logk1(x)x)=limx((k+1)!x)0



I used L'Hospital to get to limx((k+1)(k)logk1(x)x)



But from there I don't understand how to get limx((k+1)!x)



Any help would be appreciated, thanks in advance.

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