Problem :
Find the sum of :
sin−11√2+sin−1√2−1√6+sin−1√3−√2√12+⋯
My approach :
Here the n'th term is given by :
tn=sin−1[√n−√n−1√n√n+1]
From now how to proceed further please suggest thanks....
Problem :
Find the sum of :
sin−11√2+sin−1√2−1√6+sin−1√3−√2√12+⋯
My approach :
Here the n'th term is given by :
tn=sin−1[√n−√n−1√n√n+1]
From now how to proceed further please suggest thanks....
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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