I have in trouble understanding the differential forms.
For k form α and l form β we have
α∧β=(−1)klβ∧α
And for differentiation, we have
d(α∧β)=dα∧β+(−1)kα∧dβ
Apply this for usual Riemannian case, for 1-form spin connection w,
and two form curvature R=dw+w∧w
dR=d2w+dw∧w−w∧dw=dw∧w−w∧dw
Now i want to variation of differential forms. How about variation?
is the same rule holds?
In page 10 of lecture note and some computation in https://physics.stackexchange.com/questions/222100/variations-of-actions-of-lie-algebra-valued-differential-forms,
it seems they treat δ, following usual Lebiniz rule. i.e,
δR=δdw+δw∧w+w∧δw
Is their procedure right?
In usual differentiation or variation case, this does not be a big problem,
(As far as i known, the role of differentiation and variation are similar whether they treat function or functional) but in terms of differential form. I got confused.
Can you give me some formula for variation δ acting on (α∧β)?
How about Lie derivatives?
I tried to find some reference related with variation on differential form, but they only treat differentiation. Recommendation of any kinds of references are welcomed
Answer
I think what needs to be emphasised is that d and this variational δ (as opposed to the codifferential δ that is the adjoint of d) are two very different operations, that both happen to be a bit like derivatives:
- Imprecisely, d talks about the variation in the form α near x as we move around on the manifold. A simple, though coarse, analogue is the derivative d/dx.
- Whereas δ is talking about what happens to a function of α if we change α by a small amount; I find the physicists' notation is rather lacking here. The (more precise) analogue is the functional derivative, DF[α](ϕ)=limh→0(F[α+hϕ]−F[α])/h.
In particular, there is antisymmetry built into the definition of d, but δ, while superficially looking the same, is an operation talking about different sorts of variations in a different place. A more mathematical way to write the variation is to expand F[α+hϕ] to first order in h, so, for example,
(α+hϕ)∧(α+hϕ)=α∧α+h(ϕ∧α+α∧ϕ)+o(h),
and subtracting and taking h→0 gives Leibniz for the variational derivative.
No comments:
Post a Comment