I want to solve the given linear congruence
$$ 5x+1\equiv 2 \mod 6 $$
My Approach:
\begin{align}&\Rightarrow& 5x -1&\equiv 0\mod 6 \\
&\Rightarrow& 6x -x-1&\equiv 0\mod6 \tag{ as $6\equiv 0\mod6$}\\
&\Rightarrow& 0 -x-1&\equiv 0\mod6 \\
&\Rightarrow& x&\equiv -1\mod 6 \end{align}
Am I correct till now ?? If I am correct, how to proceed further?
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