I have found the following congruences:
- $x \equiv 2\mod 5$
- $x \equiv 12\mod27$
- $x \equiv 2\mod4$
How can I solve for x using the Chinese Remainder Theorem? Please include justifications for the steps you take.
How can I find $x$?
I have found the following congruences:
How can I solve for x using the Chinese Remainder Theorem? Please include justifications for the steps you take.
How can I find $x$?
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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