I have found the following congruences:
- x \equiv 2\mod 5
- x \equiv 12\mod27
- x \equiv 2\mod4
How can I solve for x using the Chinese Remainder Theorem? Please include justifications for the steps you take.
How can I find x?
How to find \lim_{h\rightarrow 0}\frac{\sin(ha)}{h} without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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