Sunday, 20 March 2016

functional equations - Solutions of f(x)cdotf(y)=f(xcdoty)




Can anyone give me a classification of the real functions of one variable such that f(x)f(y)=f(xy)? I have searched the web, but I haven't found any text that discusses my question. Answers and/or references to answers would be appreciated.


Answer



There is a classification of the functions f:RR satisfying

f(x+y)=f(x)+f(y),for all x,yR.()


These are the linear transformations of the linear space R over the field Q to itself. They are fully determined once known on a Hamel basis of this linear space (i.e., the linear space R over the field Q).



This in turn provides a classification of all the functions g:R+R+ satisfying
g(xy)=g(x)g(y),for all x,yR+,


as they have to be form g(x)=ef(logx), where f satisfies (). Note that g(1)=1, for all such g.




Next, we can achieve characterization of functions g:RR+ satisfying
g(xy)=g(x)g(y),for all x,yR,


as g(x)=g(1)g(x), which means that the values of g at the negative numbers are determined once g(1) is known, and as g(1)g(1)=g(1)=1, it has to be g(1)=1. Also, it is not hard to see that only acceptable value of g(0) is 0.



Finally, if we are looking for g:RR, we observe that, if g0, and x>0, then g(x)=g(x)g(x)>0. Thus g is fully determined once we specify whether g(1) is equal to 1 or 1.



Note that if g:RR is continuous, then either g0 or g(x)=|x|r or g(x)=|x|rsgnx, for some r>0.



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