Prove that the following identity is valid for all $z$ with $z\neq1$:
$$1+z+z^2+...+z^n=\frac{1-z^{n+1}}{1-z}$$
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
No comments:
Post a Comment