Tuesday, 31 May 2016

calculus - Finding limxtoinftyfrac(x!)frac1xx






Find limx(x!)1xx




I have no idea how to solve it, I can approximate it to be in (0,1) by squeezing but getting to the solution (1e) seems like it would require a lot more. Is this an identity?




Note: no integrals nor gamma function.


Answer



Note this
(x!xx)1/x=(ax)1/x



where ax=x!xx and then use the fact that




limx(ax)1/x=limxax+1ax





and the evaluation of limit will become easy



limxax+1ax=limx1(1+1/x)x=1e.


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