Find limx→∞(x!)1xx
I have no idea how to solve it, I can approximate it to be in (0,1) by squeezing but getting to the solution (1e) seems like it would require a lot more. Is this an identity?
Note: no integrals nor gamma function.
Answer
Note this
(x!xx)1/x=(ax)1/x
where ax=x!xx and then use the fact that
limx→∞(ax)1/x=limx→∞ax+1ax
and the evaluation of limit will become easy
limx→∞ax+1ax=limx→∞1(1+1/x)x=1e.
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