I am wondering how to prove limx→∞exxn=∞
I was thinking of using L'Hospital's rule? But then not sure how to do the summation for doing L'Hospital's rule n times on the denominator? Or whether it would be easier using longs like limx→∞ln(ex)−ln(xn)?
Thank you!
Answer
You can certainly use L'Hopital's n times. That is, for each n≥0 we have limx→∞exxn=limx→∞exnxn−1=⋯=limx→∞exn!=∞ since at each stage we are in ∞∞ indeterminate form.
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