Evaluate the integral ∫ex.(2−x2)(1−x)√1−x2dx
Set u=1√1−x⟹du=−dx2(1−x)3/2
∫ex.(2−x2)(1−x)√1−x2dx=∫ex.(2−x2)(1−x)3/2√1+xdx=∫ex2−x2.−2du√2t2−1t2dx
I have no clue about what is the easiest substitution possible inorder to solve the above integral ?
I tried u=1√1−x yet it is becoming more cumbersome I guess.
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