So, it is asked to find the real and imaginary parts of the specific complex function:
$f(z)=sin(z)+i(3z+2) $
So I use $z$ as $z=x+iy$
everything seemed clear till I met Mr. Sinus:
$u+iv= sin(x+iy)+i(3(x+iy)+2)$
and I don't really know how to seperate the imaginary and real parts of $sin(x+iy)$ argument.
Need hints...
Answer
Hint:
use addition formula: $\sin(x+iy)=\sin x \cos(iy)+\cos x \sin(iy)$ and remember that: $ \cos(iy)=\cosh(y)\;$ and $ \sin(iy)=i\sinh y$.
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