So, it is asked to find the real and imaginary parts of the specific complex function:
f(z)=sin(z)+i(3z+2)
So I use z as z=x+iy
everything seemed clear till I met Mr. Sinus:
u+iv=sin(x+iy)+i(3(x+iy)+2)
and I don't really know how to seperate the imaginary and real parts of sin(x+iy) argument.
Need hints...
Answer
Hint:
use addition formula: sin(x+iy)=sinxcos(iy)+cosxsin(iy) and remember that: cos(iy)=cosh(y) and sin(iy)=isinhy.
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