Tuesday, 8 August 2017

calculus - How to calculate limxto4(fracfracpi6arcsin(fracsqrtx4)sqrt[3]2x71) without the rule of L'Hôpital?




limx4(π6arcsin(x4)32x71)



Hello! I need to solve this limit. I had solved it with the rule of L'Hôpital, but i can't without it. I tried multiplication by conjugate expression and using Special Limits. Please help me, I must solve it using only Special Limits and simple transformations. I can't use derivatives.


Answer



Well, let's put u=arcsin(x/4) so that as x4 we have uπ/6 and x=16sin2u. The expression under limit can be written as 116π/6u1/2sinu11/2+sinu4x32x71

The desired limit is then equal to 1161cos(π/6)1limx44x32x71
The above simplifies to 183limt11t32(t1)
using substitution t=32x7. Thus the desired limit is 3/16.


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