I've been trying to solve this limit without L'Hospital's rule because I don't know how to use derivates yet. So I tried rationalizing the denominator and numerator but it didn't work.
limx→4√2x+1−3√x−2−√2
By the way, the answer is supposed to be 2√23.
Answer
limx→4√2x+1−3√x−2−√2=limx→42(x−4)(√x−2+√2)(x−4)(√2x+1+3)=limx→42(√x−2+√2)(√2x+1+3)=2√23
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