Sunday, 7 April 2019

calculus - Exponential of complex square root




Is there any way to simplify any further the exponential of a complex square root, as in the following expression:



$$ e^{ a + \sqrt{x + i\cdot y}}, $$



where $a>0, x >0$ and $y<0$. If I were to select the principal square root, I could define $ r = \sqrt{x^2 + y^2}$ and $\theta = \arctan {x/y}$. Then,



$$ e^{ a + \sqrt{r}\cdot(\cos(\theta/2) + i\cdot \sin(\theta/2) )}. $$



Is there a way to get a friendlier or simplify? I have to later on integrate this expression with respect to $y$ and it doesn't seem easy to integrate.


Answer




The integration does not seem to be very difficult.



Let
$$\sqrt{x+i y}=t \implies y=i \left(x-t^2\right)\implies dy=-2it\,dt$$
$$\int e^{a+\sqrt{x+i y}}\,dy=-2i e^a\int t e^{\sqrt{t^2}}\,dt$$ Simplify and use one integration by parts.


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