Sunday, 7 April 2019

calculus - Exponential of complex square root




Is there any way to simplify any further the exponential of a complex square root, as in the following expression:



ea+x+iy,



where a>0,x>0 and y<0. If I were to select the principal square root, I could define r=x2+y2 and θ=arctanx/y. Then,



ea+r(cos(θ/2)+isin(θ/2)).



Is there a way to get a friendlier or simplify? I have to later on integrate this expression with respect to y and it doesn't seem easy to integrate.


Answer




The integration does not seem to be very difficult.



Let
x+iy=ty=i(xt2)dy=2itdt
ea+x+iydy=2ieatet2dt Simplify and use one integration by parts.


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