i was solving the question from the book IIT FOUNDATION AND OLYMPIAD - X
and i was solving the problems of polynomials-III
. so on the page number 136, there is a question (question 17) given below:
The remainder when $x$^100 is divided by $x^2-3x+2$ is:
a) $(2$^100$-1)x + (-2$^100$ +2) $
b) $(2$^100$+1)x + (-2$^100$ -2) $
c) $(2$^100$-1)x + (-2$^100$ -2) $
d) none
as far as i tried to find the remainder, i tried long division method but it was getting more and more complicated, then i used systematic method of division but i can't get the corret option
what is the correct option. please explain me how did you find the remainder. thanks
and yes its answer is option (a)
Answer
Hint Write $x^{100}= (x^2-3x+2)q(x) + ax+b$. Now plug $x=1$ and $x=2$ to find $a$ and $b$.
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