Thursday, 4 April 2019

calculus - What is limlimitsnrightarrowinftyfracsqrtn+1+3sqrtn+24?




limnn+1+3n+24



I know that I should multiply by the conjugate if I have square roots in either the numerator or the denominator but what if I have square roots in both numerator and denominator?



Could anyone help me please?


Answer



HINT




By intuition we have that the n terms are dominant on the others and therefore in the limit



(n+1)+3(n+2)4nn=1



To check and formalize rigoursly this fact let consider



(n+1)+3(n+2)4=nn(1+1/n)+3/n(1+2/n)4/n



then take the limit.



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