Thursday, 4 April 2019

calculus - What is limlimitsnrightarrowinftyfracsqrtn+1+3sqrtn+24?




lim



I know that I should multiply by the conjugate if I have square roots in either the numerator or the denominator but what if I have square roots in both numerator and denominator?



Could anyone help me please?


Answer



HINT




By intuition we have that the \sqrt n terms are dominant on the others and therefore in the limit



\frac{\sqrt{(n+1)}+ 3}{\sqrt{(n+2)} - 4}\sim \frac{\sqrt n}{\sqrt n}=1



To check and formalize rigoursly this fact let consider



\frac{\sqrt{(n+1)}+ 3}{\sqrt{(n+2)} - 4}=\frac{\sqrt n}{\sqrt n}\frac{\sqrt{(1+1/n)}+ 3/\sqrt n}{\sqrt{(1+2/n)} - 4/\sqrt n}



then take the limit.



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