It has been given as, $\int_0^\pi x\sin^6x\cos^4x dx$
I am able to solve $\sin^6x\cos^4x$. But there is a $x$ in between. So could you please help me out.
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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