Following this enter link description here, where we're performing the derivative
ddx5xcos(x),
The first step of the differentiation is:
[au(x)]′ = ln(a)au(x)u′(x).
I’m quite confused by the intuition. Where did the ln come from? Why do we need to multiply by au(x)?
Would appreciate a step by step breakdown of why this is the first step. Is this just another differentiation rule to remember (like chain rule, product rule) that I should instinctively know when performing differentiation, or is there some manipulation that lead to the equation above? This is a new topic for me, apologies.
Answer
We have that
au(x)=eu(x)⋅loga
and then
(au(x))′=(eu(x)⋅loga)′=eu(x)⋅loga⋅(u(x)⋅loga)′=au(x)⋅u′(x)⋅loga
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