Friday, 6 June 2014

real analysis - Iff1(x)=kxf(x), then what can we say about f?

If f1(x)=kxf(x)xR for a strictly increasing f and k a constant, then what can be said about f?



I think the answer is of the form f(x)=x+c, for some cR. Any hints. Thanks beforehand

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