Use Euclid's Algorithm to find the multiplicative inverse of 13 in Z35
Can someone talk me through the steps how to do this? I am really lost on this one.
Thanks
Answer
Hint: 13 and 35 are relatively prime. Use the extended Euclidean algorithm to find the integers x and y such that:
13x+35y=1
From here, simply mod out by 35:
13x \equiv 1 \pmod{35}
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