algebra precalculus - simplify a log expression

I met a problem, I don't know if this term can be simplified properly?

$$e^{ (\ln ax^{b})^{c}}$$

since the ln term with power of c is hard to cope with, thanks for any help!

Answer

It's $e^{\ln(ax^b)*\ln(ax^b)^{c-1}} = (ax^b)^{(\ln(ax^b))^{c-1}}$ It doesn't simplify any more than that unfortunately.