Tuesday, 7 July 2015

algebra precalculus - simplify a log expression



I met a problem, I don't know if this term can be simplified properly?




$$e^{ (\ln ax^{b})^{c}}$$



since the ln term with power of c is hard to cope with, thanks for any help!


Answer



It's $e^{\ln(ax^b)*\ln(ax^b)^{c-1}} = (ax^b)^{(\ln(ax^b))^{c-1}}$ It doesn't simplify any more than that unfortunately.


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