Evaluate ∫10xarcsin(sin(1x))dx=∫∞1arcsin(sinx)x3dx
I tried to use Feynman's trick in the second one as
I(a)=∫∞1arcsin(sinax)x3dx
We have I(0)=0
Now differentiating both sides leads me to an absurd integral as I′(a)=∫∞1cosaxx2|cosax|dx
I am now unable proceed further.
Also If I keep in mind that I need value of integral at a=1 and so break the integral in intervals as (1,π2);(π2,3π2);(3π2,5π2)
and so on then this gives me the value of integral as 0. But I suspect it isn't correct because one online software suggests it's value to be 12
Moreover the signum function is always reminding me of the Grandi's series which also in some definition equals 1/2
Any help would be greatly appreciated.
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