2+2=4−92+92=√(4−92)2+92=√16−2×4×92+(92)2+92=√16−36+(92)2+92=√−20+(92)2+92=√25−45+(92)2+92=√52−2×5×92+(92)2+92=√(5−92)2+92=5+92−92=5
Where did I go wrong
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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