complex numbers - Squarring the Euler's formula

$$\begin{align}&e^{\pi i} + 1 = 0 &\text{ (Euler's Formula)}\\ \implies &e^{\pi i} = -1&\\ \implies &e^{2\pi i} = 1& \text{ (Squaring both sides)}\\ \implies &e^{2\pi i} = e^0 (e^0 = 1)&\\ \implies &2\pi i = 0&\end{align}$$

how is this possible?