I am trying to show that |R×R|≤|R|.
I don't know how to define f:R×R→R in a way that would make f injective.
My professor gave us the hint that (0,1)∼R would imply that |(0,1)×(0,1)|≤|(0,1)|, but I don't understand how that is helpful here.
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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