Find the value of the series ∞∑n=1n2n
The series on expanding is coming as 12+222+..
I tried using the form of (1+x)n=1+nx+n(n−1)2x2+.. and then differentiating it but still it is not coming .What shall I do with this?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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