Rewrite the function 2+4sin(πt+π6) into a sum of exponential functions. By that I mean using Euler's formula sin(x)=eiπx−e−iπx2i.
If it wasn't for the π6 term, this wouldn't be a problem for me, but I'm not sure what I can do to fix that.
Answer
Using additional formulas:
2+4sin(πt+π6)=2+4sin(πt)cosπ6+4cos(πt)sinπ6=
=2+2√3eiπ2t+e−iπ2t2+2eiπ2t−e−iπ2t2i
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