Rewrite the function $2 + 4\sin(\pi t + \frac{\pi}{6})$ into a sum of exponential functions. By that I mean using Euler's formula $\sin(x) = \dfrac{e^{i\pi x} - e^{-i\pi x}}{2i}$.
If it wasn't for the $\frac{\pi}{6}$ term, this wouldn't be a problem for me, but I'm not sure what I can do to fix that.
Answer
Using additional formulas:
$$
2+4\sin(\pi t+\frac{\pi}{6})=
2+4\sin(\pi t)\cos\frac{\pi}{6}+4\cos(\pi t)\sin\frac{\pi}{6}=
$$
$$
=2+2\sqrt{3}\dfrac{e^{i\pi^2t} + e^{-i\pi^2t}}{2}+2\dfrac{e^{i\pi^2t} - e^{-i\pi^2t}}{2i}$$
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