I'd like to know how to solve something like this:
f(f(x2)−f(x1))=27.5f(f(x3)−f(x1))=21.6f(f(x4)−f(x1))=15.1f(f(x5)−f(x1))=10.2f(f(x6)−f(x1))=8.8f(f(x7)−f(x1))=8.4f(f(x8)−f(x1))=7.8f(f(x9)−f(x1))=6.4f(f(x4)−f(x3))=46.5f(f(x5)−f(x3))=17.6f(f(x5)−f(x4))=28f(f(x7)−f(x4))=20.1f(f(x9)−f(x7))=22
where I'm looking for f(x) and x1,x2,…,x9. It is given that $0
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