Friday, 2 August 2013

sequences and series - How to compute suminftyn=0left(frac4(3)nfrac33nright)?



I'm currently trying to compute the following series (found on page 65 of this textbook):



n=0(4(3)n33n)



I've tried to somehow transform it into a geometric series (which I'm fairly sure is the strategy for this series), but I've been unable to. Any help in solving this would be appreciated (though I'd prefer a hint over a solid answer).



Answer



Hint:



4(3)n33n=4(13)n3(13)n


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