I'm currently trying to compute the following series (found on page 65 of this textbook):
∞∑n=0(4(−3)n−33n)
I've tried to somehow transform it into a geometric series (which I'm fairly sure is the strategy for this series), but I've been unable to. Any help in solving this would be appreciated (though I'd prefer a hint over a solid answer).
Answer
Hint:
4(−3)n−33n=4(−13)n−3(13)n
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