Limit of 6xsin(4x) as x approaches infinity. I know its 24 thanks to wolfram alpha. I don't know how to get there. Just need to understand how this is done so I am not lost in the future.
Answer
Make a change of variable: (n=1/x)
limx→∞6xsin4x=limn→06sin4nn
=limn→024sin4n4n
=limn→024(sin4n4n)
=24
No comments:
Post a Comment