Sunday, 18 October 2015

limit of 6xsin(frac4x) as x approaches infinity



Limit of 6xsin(4x) as x approaches infinity. I know its 24 thanks to wolfram alpha. I don't know how to get there. Just need to understand how this is done so I am not lost in the future.


Answer



Make a change of variable: (n=1/x)
limx6xsin4x=limn06sin4nn


=limn024sin4n4n

=limn024(sin4n4n)


=24


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