Try to find out if it is possible to partition 6 consecutive positive integers into two sets, $A_1$ and $A_2$ such that the product of the elements in $A_1$ is equal to the product of the elements in $A_2$?
Also, check if this is possible for 20 consecutive positive integers?
I said:
Let $K=$ positive integer, then we need to partition:
$$K, K+1, K+2, K+3, K+4, K+5 $$
This wasnt helping me so i worked with numbers.
I started out with:
$$ 1,2,3,4,5,6 $$
and i can't seem to partition it.
So i worked with:
$$ 2,3,4,5,6,7 $$
I tried:
$A_1=4,7,3=84$
$A_2=2,5,6=60$
and I tried more cases but trial and error does not seem to be effective. Any strategies or patterns anybody else notice?
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