∞∑n=1log(1+an) converges absolutely⇔∞∑n=1an converges absolutely.
How to prove this,
Suppose ∞∑n=1an converges absolutely. Let un=an and vn=log(1+an), then lim How to prove the converse part?
Answer
Hint: From the definition of \ln'(1), we have
\lim_{u\to 0}\frac{\ln (1+u)}{u} = 1.
Thus there is a>0 such that
\frac{1}{2}\le \left|\frac{\ln (1+u)}{u}\right| \le \frac{3}{2}
for u\in (-a,a),u\ne0.
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