Help me please with this improper integral:
∫∞0e−√xdx
Thanks.
I solved it partially, and stuck after integration by parts.
Answer
I=lima→∞a∫0e−√xdx=lima→∞(2−2⋅√a+1e√a)=2−2⋅lima→∞√a+1e√a=2
The last limit can be evaluated using substitution t=√a and L'Hopital rule .
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