Friday, 13 November 2015

calculus - Improper integral intinfty0esqrtxtextdx



Help me please with this improper integral:



0exdx




Thanks.



I solved it partially, and stuck after integration by parts.


Answer



I=limaa0exdx=lima(22a+1ea)=22limaa+1ea=2



The last limit can be evaluated using substitution t=a  and L'Hopital rule .


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