I was wondering, given some polar function r(θ) is it possible to convert it into a complex number in exponential form, then differentiate that and then convert it back and have the appropriate derivative of the polar function?
For example take the polar function r=cos(aθ), also known as a rose curve for a∈Q. Is it possible to 'complexify' this function (not too sure how possible that is) and then take the derivative?
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