Let r>4 and n>1 be positive integers. Can we simplify this sum:
S=n∑m=12mrm2
I have no idea to start.
Answer
Such a sum is related with a Jacobi theta function, hence it cannot be "simplified" too much, but it can be approximated in a quite effective way.
Let K=logr. Then:
S=1Kn∑m=12mKe−Km2
can be seen as a Riemann sum, hence:
S≈n2K∫102Kxe−Kn2x2dx=1−e−Kn2K.
No comments:
Post a Comment