Tuesday 29 April 2014

abstract algebra - Show that either $f$ is irreducible or $f$ factors into irreducible polynomials of degree $3$ over $K$.


Let $f(x)$ be an irreducible polynomial of degree $6$ over field $K$.



If $L$ is a field extension of $K$ and $[L: K]=2$ then show that either $f$ is irreducible or $f$ factors into irreducible polynomials of degree $3$ over $K$.




Attempt:




If $f$ is irreducible then we are done.



Otherwise $f$ factors into either $1+5$ or $2+4$ or $3+3$ degree polynomials.



I am unable to derive a contradiction for the first two cases.



Please give some hints.

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...