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How to solve this limit?
$$\lim_{x\to1}\frac{x^2-1}{\ln(x)}=\frac00$$
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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