Thursday, 10 April 2014

calculus - Evaluating the limit of limxtoinfty(sqrtfracx3x+2x).



How do I evaluate this limit:
limx(x3x+2x)



I tried to evaluate this using rationalizing the denominator, numerator and L'Hospital rule for nearly an hour with no success.



Answer



Rationalizing, observe that:
limx(x3x+2x)=limx(x3x+2x)(x3x+2+xx3x+2+x)=limxx3x+2x2x3x+2+x=limx2x2x+2x3x+2+x1x1x=limx2xx+2limx(xx+2+1)=21+1=1


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