I just learn some basic definition about
Let $f, g:[0,1] \rightarrow \Bbb R$ be
$ f(x) =
\begin{cases}
1, & \text{if $x \in \Bbb Q$} \\
0, & \text{otherwise}
\end{cases}$
$g(x) =
\begin{cases}
1, & \text{if $x=1/n, n=1,2,...$} \\
0, & \text{otherwise}
\end{cases}$
We know $f$ is not Riemann integrable, but $g$ is.
So my first question is, is it true that if the set of discontinuous points is a dense set, then that function is not Riemann integrable.
My second question is we know $h:[0,1] \rightarrow \Bbb R$ by $h(x)=1$ is integrable and has value $1$. So if we have a dense set $D$ in $[0,1]$ which cardinality of $D$ and $D^c$ are equal, and define $ u(x) =
\begin{cases}
1, & \text{if $x \in D$} \\
0, & \text{otherwise}
\end{cases}$
Can we define a similar 'integral' to say the value of the 'integral' = $1/2$
Thank you!
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