Tuesday, 15 April 2014

trigonometry - Find the maximum and minimum of cosxsinycosz.




Given xyzπ/12, x+y+z=π/2, find the maximum and minimum of cosxsinycosz.




I tried using turn siny to cos(x+z), and Jensen Inequality, but filed. Please help. Thank you.



*p.s. I'm seeking for a solution without calculus.


Answer




Let P=cosxsinycosz=cosz2[2cosxsiny]=cosz2[sin(x+y)sin(xy)]cosz2sin(x+y)



So Pcoszcosz2=14(1+cos2z)14[1+cos2π12]=2+38



Above equality hold when sin(xy)=0x=y and given x+y=π2z and xyzπ12



And for max(P), We must have z=π12 and x=y=5π24


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