Tuesday, 29 April 2014

algebra precalculus - Question about Properties of Exponents

I'm just doing some assignments and I was a little confused by this, could someone explain why the second equation is not equal like the first one? From what I've learned, if you take the inverse you switch the exponential sign (positive to neg for example)
$$\frac{3^{1}} {1^{}} = \frac{1^{}} {3^{-1}}$$
$$\frac{1^{1}} {3^{}} ≠ \frac{3^{}} {1^{-1}}$$

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...