This expression should be extremely easy to simplify, but for some reason I can't do it.
$$\frac{x^4-1}{x-1}$$
I know it simplifies down to this, but I don't know how to get there
$$x^3+x^2+x+1$$
This is a very basic question on my calculus worksheet, I would appreciate if anyone could explain how the first expression simplifies down to the second.
Answer
Write it as the difference of two squares $$\frac{(x^2-1)(x^2+1)}{(x-1)}$$
$$\frac{(x+1)(x-1)(x^2+1)}{(x-1)}$$
$$(x+1)(x^2+1)=x^3+x^2+x+1$$
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