I'm in trouble with Taylor series..... how can I solve limits without Bernoulli-de L'Hôpital method?? For example, $$\lim_{x \to +\infty} \frac{x-\sin{x}}{2x+\sin{x}}.$$
The answer, if I'm not wrong is $\frac{1}{2}$... How, can I show that?
Thanks.
Thursday 28 July 2016
calculus - How to solve limits with Taylor expansion?
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