Say we have the function $f(x)=(x-2)^3+3$, whose graph is
and we want to find at what regions does $f$ have a positive/negative concavity, and where the inflection points are.
I learned to answer these questions doing:
\begin{align*}
f^{'}(x) &= 3(x-2)^2 \\
f^{''}(x) &= 2\cdot 3(x-2)^1 \\
f^{''}(x) &= 0 \implies x = 2 \\
f(2)&= 3
\end{align*}
$\therefore$
Concavity is positive within $(2, \infty)$, negative within $(- \infty, 2)$
Inflection point(s): $(2, 3)$
But why does this work? Will I have issues when the function has multiple inflection points or do I just have to be more careful? And what if the degree of a function were very high, say of degree 6? Would I have to keep computing the derivative until I get a derivative of degree 1 or does it only take until the second derivative?
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