n∑k=1k3=(n∑k=1k)2
I can't quite understand this expression, and in fact this is my biggest difficulty in finding a solution. Can someone please explain to me ?
n∑k=1k=n(n+1)2
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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